[MITgcm-support] Bottom drag setup question

[Yilang Xu]

I just checked sideDragFactor setup in mom_v_sidedrag.F, scenario 2 is solved for no slip side. 

Now I mostly wonder the logic behind scenario 1, for the case with free-slip bottom and a specified bottom drag. 

Any clarification is appreciated. 

 

Best,

Yilang

 

From: MITgcm-support <mitgcm-support-bounces at mitgcm.org> on behalf of Yilang Xu <yxu at whoi.edu>
Reply-To: <mitgcm-support at mitgcm.org>
Date: Tuesday, June 4, 2019 at 22:12
To: "mitgcm-support at mitgcm.org" <mitgcm-support at mitgcm.org>
Subject: [MITgcm-support] Bottom drag setup question

 

Hi, 

 

I am checking the behavior of the bottom drag, following the old post http://mailman.mitgcm.org/pipermail/mitgcm-support/2011-June/007258.html . 

My question involves 2 scenarios, and I am wondering if my interpretation is right. 

 

1. Scenario 1 setup: 

no_slip_sides=.FALSE.,

no_slip_bottom=.FALSE.,

bottomDragQuadratic=2.5E-3,

Although both the bottom and the side are free slip, there are still bottom friction and energy dissipation at the bottom. I saw some papers do this using MITgcm, but it is not very intuitive to me. 

 

2. Scenarios 2 setup: 

no_slip_sides=.TRUE.,

no_slip_bottom=.TRUE.,

bottomDragQuadratic=2.5E-3,

Now the bottom is no slip with a bottom drag coefficient specified. However, since the side is no slip as well, is there also a drag coefficient that can be specified for the sides? 

 

There are some explanations in the documentation http://mitgcm.org/public/r2_manual/latest/online_documents/node58.html , but I am hoping further clarifications about this. 

 

Thanks,

Yilang

 

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