<html><head><meta http-equiv="Content-Type" content="text/html; charset=us-ascii"></head><body style="word-wrap: break-word; -webkit-nbsp-mode: space; line-break: after-white-space;" class="">Did you try linear extrapolation (XG(Nx+1) = 2*XC(Nx)-XG(Nx)?<div class=""><br class=""></div><div class="">Martin<br class=""><div><br class=""><blockquote type="cite" class=""><div class="">On 14. Apr 2022, at 07:47, ESTANISLAO GAVILAN PASCUAL-AHU <<a href="mailto:e.gavilan@hhu.edu.cn" class="">e.gavilan@hhu.edu.cn</a>> wrote:</div><br class="Apple-interchange-newline"><div class=""><meta http-equiv="Content-Type" content="text/html; charset=utf-8" class=""><div style="line-height: 1.7; font-size: 14px; font-family: Arial;" class=""><div class="">Hi Community,<br class=""><br class="">I would like to transform a curvilinear grid into another curvilinear grid. I found several tools to use such cdo or esmf. These libraries need the lat/lon grid and cells corners of each grid point. I know I can get most of the cell corners using the variable xG and yG, but I am not sure what to do in the last row and column. Thanks in advance for your help</div><div class=""><br class=""></div><div class="">Kind regards,</div><div class=""><br class=""></div><div class="">Estanislao</div></div><br class="">_______________________________________________<br class="">MITgcm-support mailing list<br class=""><a href="mailto:MITgcm-support@mitgcm.org" class="">MITgcm-support@mitgcm.org</a><br class="">http://mailman.mitgcm.org/mailman/listinfo/mitgcm-support<br class=""></div></blockquote></div><br class=""></div></body></html>