[MITgcm-support] Output record

[Vincent Le Fouest]

Dear Yuan,

I guess what you suggest works for variable as for instance nitrate in
mol/m3. But the variable I want to save is a rate in mol/m3/d. So in that
case, to cumulate my rate, shouldn't I multiply my rate like
T_cumulate=Ttave*2592000 only and not divide by 1200?

2011/11/23 Yuan Lian <lian at ashimaresearch.com>

>  taveFreq=2592000 means averaging variables over a month (assuming 30
> days). To obtain monthly cumulated variable, you can simply multiply the
> averaged variable by taveFreq/deltaT. For instance,
> T_cumulate=Ttave*2592000/1200 in your case. taveFreq is rather the time
> averaging period.
>
> Yuan
>
>
> On 11/23/11 5:09 AM, Vincent Le Fouest wrote:
>
> Dear users,
>
> My understanding is that MITgcm computes averages of fields as follows:
> var_timeave = var_timeave + var*deltaT, where dt is the model time step in
> seconds.
>
> I want to cumulate a variable over a month.
>
> Considering my time step deltaT is 1200 seconds and that MITgcm averages
> monthly (taveFreq=2592000. in data). Is it correct to multiply my
> monthly-averaged field by 86400 (a day in seconds) and again by the number
> of days of the month to obtain my monthly-cumulated field?
>
> Thanks in advance
>
> Vincent
>
>
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